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A.1. A two-level model


Date: 2015-10-07; view: 491.


Before discussing the iterative solutions for f (x) and , it may be useful to first extract some essential features of the soluble square-well example. Let us first concentrate on Case (i) of (A.46), with the parameters α and δ satisfying

 

e-2qα e-2q(α-δ) 1. (A.76)

We shall also neglect ()−1 or ()−1, when compared to 1. Thus, from Figs. (A.27) and (A.28), we have

 

(A.77)

in addition, from Figs. (A.30) and (A.38) we find

 

(A.78)

From (A.54), we have

 

(A.79)

On account of Figs. (A.15), (A.20), (A.27) and (A.29),

 

(A.80)

which, for

 

(A.81)

gives

 

(A.82)

On the other hand, from Figs. (A.13), (A.19), (A.42) and (A.43), we see that

 

(A.83)

Thus, under the condition (A.76), we find

 

(A.84)

As we shall see, these inequalities can be understood in terms of a simple two-level model.

Introduce

 

λ=E-Eb. (A.85)

We note that from (A.82),

 

(A.86)

and from Figs. (A.79) and (A.83),

 

(A.87)

Consequently, the three small energy parameters in (A.84) are related by

 

(A.88)

From e-2qδ 1 and (A.76) , we see that

 

(A.89)

in accordance with Figs. (A.79) and (A.84). To understand the role of the parameter λ, we may start with the definition of Vb (x), given by (A.5), keep the parameters β = γα and fixed, but let the spacing 2α between the two potential wells approach ∞; in the limit 2α → ∞, we have EbE. Thus, λ = EEb is the energy shift due to the tunneling between the two potential wells located at x < −α and x > α in Vb (x).

There is an alternative definition for λ, which may further clarify its physical significance. According to (A.3), Vb (x) is even in x; therefore, its eigenstates are either even or odd in x. In (A.9), χb (x) is the ground state of T + Vb (x), and therefore it has to be even in x. The corresponding first excited state χod is odd in x; it satisfies

 

(T+Vb(x))χod(x)=Eodχod(x). (A.90)

We may define λ by

 

2λ≡Eod-Eb (A.91)

and regard Figs. (A.85) and (A.86) both as approximate expressions, as we shall see.

Multiplying (A.9) by χod (x) and (A.90) by χb (x), then taking their difference we derive

 

(A.92)

From (A.12), we may choose the normalization of χb so that

 

(A.93)

Correspondingly,

 

(A.94)

with

 

(A.95)

As in Figs. (A.25) and (A.26), qod and pod are determined by

 

-podβcotpodβ=qodβcothqodα (A.96)

and

 

(A.97)

At x = 0, we have

 

(A.98)

Integrating (A.92) from x = 0 to x = γ, we find

 

(A.99)

From Figs. (A.27), (A.28) and (A.29), we see that

 

(A.100)

Likewise, we can also show that

 

(A.101)

Thus, qod qb W, and the integral in (A.99) is

 

(A.102)

Since qod W, we derive from (A.91)

 

(A.103)

in agreement with (A.86).

We are now ready to introduce the two-level model. We shall approximate the Hamiltonian T + V (x), T + Va (x), and T + Vb (x) of Figs. (A.7), (A.8) and (A.9) by the following three 2 × 2 matrices:

 

(A.104)

 

(A.105)

and

 

(A.106)

with ψ, χa, and χb as their respective ground states which satisfy

 

(A.107)

The negative sign in the off-diagonal matrix element −λ in Figs. (A.104), (A.105) and (A.106) is chosen to make

 

(A.108)

simulating the evenness of χa (x) and χb (x). Likewise, the analog of χod is the excited state of hb, with

 

(A.109)

and

 

hbχod=Eodχod. (A.110)

It is straightforward to verify that

 

(A.111)

where

 

(A.112)

 

(A.113)

When , we have

 

(A.114)

in agreement with (A.88).

Next, we wish to examine the relation between the two-level model and the soluble square-well example when λ is . Assume, instead of (A.76),

 

(A.115)

Hence, in the square-well example, (A.83),

 

and (A.86),

 

remain valid; on the other hand, Figs. (A.54) and (A.78) now lead to

 

(A.116)

Thus, the above expressions for EE and λ give

 

Together with (A.116), this shows that the soluble square-well example yields

 

in agreement with (A.113) given by the two-level model.

In both the square-well problem and the simple two-level model, we can also examine the limit, when . In that case, (A.113) gives

 

which leads to

 

in agreement with the exact square-well solution. Furthermore, if we include the first-order correction in O (μ2), (A.115) gives

 

(A.117)

As we shall discuss, for the exact square-well solution, (A.117) is also valid. Thus, the simple two-level formula (A.113) may serve as an approximate formula for the exact square-well solution over the entire range of .


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Appendix A. A soluble example | A.2. Square-well example (Cont.)
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